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Question #44663

Difficulty: 8/10 | 🟢 Free

The Question

A 16.2 g16.2\text{ g} equimolar mixture of ethyl ethanoate and diethyl ether is heated with 19.2 g19.2\text{ g} of anhydrous \ce{HI} at 373 K373\text{ K} in a sealed tube. The reaction proceeds under kinetic control. Assuming no further reaction of the initial cleavage products occurs under these limited \ce{HI} conditions, what is the total combined mass of all halogenated organic products and alcohols present in the final reaction mixture?

(Given molar masses in g/mol\text{g/mol}: H=1\text{H} = 1, C=12\text{C} = 12, O=16\text{O} = 16, I=127\text{I} = 127)

Options

  • A.

    25.7 g

  • B.

    28.0 g

  • C.

    31.7 g

  • D.

    35.8 g

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Numerical_Precision

Improve calculation stamina and avoid rounding errors in high-stakes competitive examinations.

Concepts Behind This Question

Limiting Reagent Stoichiometry|Ether Cleavage Patterns|Nucleophilic Acyl Substitution

Why This Question Is Tricky

Common Mistakes

This problem tests the understanding of kinetic vs thermodynamic control and leaving group ability in nucleophilic substitution.

Students often fall into the trap of assuming the more basic ether reacts first (yielding 28.0 g), or they calculate stoichiometry simultaneously without identifying the kinetically preferred pathway.

Another trap is assuming acyl-oxygen cleavage (Nucleophilic Acyl Substitution) instead of alkyl-oxygen cleavage for the ester (yielding 31.7 g).

The superior leaving group ability of acetic acid over ethanol dictates that alkyl-oxygen ester cleavage by HI is significantly faster than ether cleavage, requiring sequential stoichiometric analysis.

Quick Facts About This Question

Question Information

SubjectChemistry
ChapterSome Basic Concepts of Chemistry - Class 11 Part 1
ConceptLimiting Reagent Stoichiometry
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree