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Question #44683

Difficulty: 8/10 | 🟢 Free

The Question

A 540 mL540 \text{ mL} sample of a saturated aqueous solution of \ce{AgNO3} at 298 K298 \text{ K} is subjected to electrolysis using inert electrodes. At 298 K298 \text{ K}, the solubility of \ce{AgNO3} is 170 g170 \text{ g} per 100 g100 \text{ g} of water, and the density of the saturated solution is 1.50 g/mL1.50 \text{ g/mL}. A constant direct current of 19.3 A19.3 \text{ A} is passed through the solution for 5.00 hours5.00 \text{ hours}. Assuming 100%100\% current efficiency, what is the mass of silver deposited at the cathode? \ (Given: F=96500 C/molF = 96500 \text{ C/mol}, Molar mass of \ceAg=108 g/mol\ce{Ag} = 108 \text{ g/mol}, \ceAgNO3=170 g/mol\ce{AgNO3} = 170 \text{ g/mol})

Options

  • A.

    324.0 g324.0 \text{ g}

  • B.

    388.8 g388.8 \text{ g}

  • C.

    216.0 g216.0 \text{ g}

  • D.

    510.0 g510.0 \text{ g}

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Numerical_Precision

Improve calculation stamina and avoid rounding errors in high-stakes competitive examinations.

Concepts Behind This Question

Density-Volume-Mass Relationship|Faraday's First and Second Laws|Electrode Potential Dependencies|Solubility of Solids in Liquids

Why This Question Is Tricky

Common Mistakes

This question tests the intersection of electrochemistry and intensive solution properties.

The primary trap is the 'Limiting Reagent' oversight: students often blindly apply Faraday's Law (m=MItnFm = \frac{MIt}{nF}) to calculate the theoretical yield (388.8 g388.8 \text{ g}) without verifying if the solution contains enough electrolyte.

The secondary trap is the 'Density Assumption': students frequently assume the density of an aqueous solution is 1 g/mL1 \text{ g/mL} or equate the solution volume to the solvent mass, which drastically alters the calculated moles of \ce{Ag+} (yielding 216.0 g216.0 \text{ g}).

By using a highly concentrated saturated solution, the textbook assumption of d≈1 g/mLd \approx 1 \text{ g/mL} is invalidated, forcing a rigorous derivation of mass fraction.

Quick Facts About This Question

Question Information

SubjectChemistry
ChapterSome Basic Concepts of Chemistry - Class 11 Part 1
ConceptDensity-Volume-Mass Relationship
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree