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Question #44720
The Question
In an industrial reverse osmosis (RO) plant, an aqueous solution of a reactive pollutant \ce{A} (bulk concentration ) is processed at . The RO membrane perfectly rejects \ce{A} (). Due to concentration polarization, a boundary layer exists at the membrane surface with a mass transfer coefficient . The steady-state water flux through the membrane is .
At the membrane surface, \ce{A} undergoes a first-order degradation reaction with a surface rate constant . This reaction occurs exclusively at the membrane surface.
Assuming steady-state film theory, what is the rate of degradation of \ce{A} per unit membrane area ()?
(Note: is the base of the natural logarithm)
Options
- A.
- B.
- C.
- D.
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Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Numerical_Precision
Improve calculation stamina and avoid rounding errors in high-stakes competitive examinations.
Concepts Behind This Question
Reverse Osmosis Dynamics|Stoichiometric Coefficient Division|Rate Law Derivation from Mechanism
Why This Question Is Tricky
Common Mistakes
This problem tests the intersection of Reverse Osmosis Dynamics and Chemical Kinetics.
The 'Hidden Variable' is the modification of the standard concentration polarization boundary condition.
Students typically memorize the standard formula , which assumes zero solute flux at the membrane surface ().
However, the presence of a surface degradation reaction acts as a continuous sink, changing the boundary condition to .
Failing to account for this coupled transport-reaction mechanism leads to the incorrect application of the standard formula (Option B) or ignoring polarization entirely (Option C).
Quick Facts About This Question
Question Information
| Subject | Chemistry |
| Chapter | Solutions - Class 12 |
| Concept | Reverse Osmosis Dynamics |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |