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Question #44720

Difficulty: 8/10 | 🟢 Free

The Question

In an industrial reverse osmosis (RO) plant, an aqueous solution of a reactive pollutant \ce{A} (bulk concentration Cb=10 mol m−3C_b = 10 \text{ mol m}^{-3}) is processed at 298 K298 \text{ K}. The RO membrane perfectly rejects \ce{A} (R=100%R = 100\%). Due to concentration polarization, a boundary layer exists at the membrane surface with a mass transfer coefficient km=1.0×10−5 m s−1k_m = 1.0 \times 10^{-5} \text{ m s}^{-1}. The steady-state water flux through the membrane is Jw=2.0×10−5 m s−1J_w = 2.0 \times 10^{-5} \text{ m s}^{-1}.

At the membrane surface, \ce{A} undergoes a first-order degradation reaction \ceA−>B\ce{A -> B} with a surface rate constant ks=1.0×10−5 m s−1k_s = 1.0 \times 10^{-5} \text{ m s}^{-1}. This reaction occurs exclusively at the membrane surface.

Assuming steady-state film theory, what is the rate of degradation of \ce{A} per unit membrane area (r′′r'')?

(Note: ee is the base of the natural logarithm)

Options

  • A.

    2×10−4e2e2+1 mol m−2s−1\frac{2 \times 10^{-4} e^2}{e^2 + 1} \text{ mol m}^{-2} \text{s}^{-1}

  • B.

    1×10−4e2 mol m−2s−11 \times 10^{-4} e^2 \text{ mol m}^{-2} \text{s}^{-1}

  • C.

    1×10−4 mol m−2s−11 \times 10^{-4} \text{ mol m}^{-2} \text{s}^{-1}

  • D.

    2×10−4e2e2−1 mol m−2s−1\frac{2 \times 10^{-4} e^2}{e^2 - 1} \text{ mol m}^{-2} \text{s}^{-1}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Numerical_Precision

Improve calculation stamina and avoid rounding errors in high-stakes competitive examinations.

Concepts Behind This Question

Reverse Osmosis Dynamics|Stoichiometric Coefficient Division|Rate Law Derivation from Mechanism

Why This Question Is Tricky

Common Mistakes

This problem tests the intersection of Reverse Osmosis Dynamics and Chemical Kinetics.

The 'Hidden Variable' is the modification of the standard concentration polarization boundary condition.

Students typically memorize the standard formula Cm=Cbexp⁡(Jw/km)C_m = C_b \exp(J_w/k_m), which assumes zero solute flux at the membrane surface (JA=0J_A = 0).

However, the presence of a surface degradation reaction acts as a continuous sink, changing the boundary condition to JA=ksCmJ_A = k_s C_m.

Failing to account for this coupled transport-reaction mechanism leads to the incorrect application of the standard formula (Option B) or ignoring polarization entirely (Option C).

Quick Facts About This Question

Question Information

SubjectChemistry
ChapterSolutions - Class 12
ConceptReverse Osmosis Dynamics
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree