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Question #44722
The Question
An aqueous solution is prepared by dissolving grams of a weak monobasic acid \ce{HA} (molar mass ) in water to make of solution at . This solution is found to be isotonic with a aqueous solution of glucose at the same temperature. Given the acid dissociation constant of \ce{HA} is at , determine the value of .
Options
- A.
- B.
- C.
- D.
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Numerical_Precision
Improve calculation stamina and avoid rounding errors in high-stakes competitive examinations.
Concepts Behind This Question
Isotonic, Hypertonic, Hypotonic|Van’t Hoff Factor (i) Application|Degree of Dissociation/Association
Why This Question Is Tricky
Common Mistakes
This problem tests the dependency of the van't Hoff factor () on the degree of dissociation () for weak electrolytes.
A common trap is assuming isotonicity implies equal molarity (, leading to ) or assuming complete dissociation (, leading to ).
Furthermore, solving the exact equilibrium expression yields a quadratic with two positive roots; students must apply the physical constraint (hence ) to reject the extraneous root (, leading to ).
Quick Facts About This Question
Question Information
| Subject | Chemistry |
| Chapter | Solutions - Class 12 |
| Concept | Isotonic, Hypertonic, Hypotonic |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |