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Question #44748
The Question
An aromatic primary amine (molecular formula ) yields toluene upon diazotization at followed by reduction with . A aqueous solution of at exhibits a pH of . Another isomer of , which is also a primary aromatic amine, has a of . The of aniline is . Let , , and be the degrees of dissociation of , , and aniline respectively, in their aqueous solutions. Which of the following correctly identifies , the relationship between the degrees of dissociation, and the of ?
Options
- A.
2-Methylaniline, ,
- B.
3-Methylaniline, ,
- C.
4-Methylaniline, ,
- D.
2-Methylaniline, ,
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Exception_Exposure
Learn to identify edge cases and boundary exceptions that JEE examiners hide in math problems.
Concepts Behind This Question
Degree of Dissociation (Alpha)|Ortho-Effect in Anilines|Diazotization Temperature Sensitivity
Why This Question Is Tricky
Common Mistakes
The problem tests the intersection of ionic equilibrium and organic electronic effects.
Students often assume that any electron-donating group (like ) will increase the basicity of aniline, leading them to incorrectly reject 2-methylaniline as a weaker base than aniline.
The 'hidden variable' is the Ortho-Effect (steric inhibition of solvation), which anomalously decreases the of ortho-substituted anilines.
This forces a conceptual conflict where the calculated from physical data must be reconciled with an exception in organic chemistry to identify the correct isomer and its dissociation behavior.
Quick Facts About This Question
Question Information
| Subject | Chemistry |
| Chapter | Electrochemistry - Class 12 |
| Concept | Degree of Dissociation (Alpha) |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |