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Question #44764
The Question
A aqueous solution of the violet hydrate isomer of chromium(III) chloride () is heated from to . At , the complex completely isomerizes to its dark green hydrate isomer. The temperature coefficient of equivalent conductivity for all ions is , such that . Assuming the equivalent ionic conductivities () of all cationic and anionic species present are identical at any given temperature, what is the net percentage change in the molar conductivity () of the solution?
Options
- A.
-33.3%
- B.
+33.3%
- C.
-66.7%
- D.
+100.0%
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Exception_Exposure
Learn to identify edge cases and boundary exceptions that JEE examiners hide in math problems.
Concepts Behind This Question
Molar Conductivity Trend|Temperature Coefficient (Q10)
Why This Question Is Tricky
Common Mistakes
This problem tests the interplay between kinetic and thermodynamic factors in electrolytic conductance.
Students typically apply the general rule that heating decreases solvent viscosity, thereby increasing ionic mobility and conductivity (leading to the +100% trap).
However, they must recognize the 'Chemical Exception': the thermal activation triggers an endothermic anation (isomerization from the violet to the dark green hydrate), which drastically reduces the van't Hoff factor and the total charge (n-factor) of the electrolyte.
This speciation change overrides the kinetic mobility increase, resulting in a net decrease in molar conductivity.
Quick Facts About This Question
Question Information
| Subject | Chemistry |
| Chapter | Electrochemistry - Class 12 |
| Concept | Molar Conductivity Trend |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |