Start Learning Free

Before You Begin

Question #44777

Difficulty: 8/10 | 🟢 Free

The Question

A cylindrical corrosion pit of depth L=1.0×10−2L = 1.0 \times 10^{-2} m and cross-sectional area A=1.0×10−4A = 1.0 \times 10^{-4} m2^2 is formed on an iron surface. The pit is filled with an aqueous solution of a weak monoprotic acid \ce{HA} at a uniform concentration of C=0.1C = 0.1 M. Due to a localized gradient, the degree of dissociation of \ce{HA} varies with depth zz (where z=0z=0 at the pit opening and z=Lz=L at the iron base) according to the relation α(z)=α0LL+z\alpha(z) = \frac{\alpha_0 L}{L + z}, with α0=0.025\alpha_0 = 0.025. The limiting molar conductivity of \ce{HA} is Λm∞=4.0×10−2 S m2mol−1\Lambda_m^\infty = 4.0 \times 10^{-2} \ \text{S m}^2 \text{mol}^{-1}. A constant potential difference of V=1.5V = 1.5 V drives the anodic dissolution of iron (\ce{Fe -> Fe^{2+} + 2e^-}) at the base of the pit. Assuming the resistance of the electrolyte in the pit is the only resistance in the circuit, calculate the mass of iron lost due to corrosion after t=96500t = 96500 s. \n(Given: Atomic mass of Fe = 56 g/mol, 1F=965001 F = 96500 C/mol, assume Λm≈Λm∞\Lambda_m \approx \Lambda_m^\infty for the weak acid).

Options

  • A.

    28 mg

  • B.

    42 mg

  • C.

    56 mg

  • D.

    29.1 mg

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Numerical_Precision

Improve calculation stamina and avoid rounding errors in high-stakes competitive examinations.

Concepts Behind This Question

Corrosion as Electrochemical Process|Faraday's First and Second Laws|Resistance and Resistivity Interconversion

Why This Question Is Tricky

Common Mistakes

This problem tests the student's ability to model a non-uniform electrolyte where resistivity varies spatially.

The primary trap is treating the electrolyte with a bulk resistance formula R=ρL/AR = \rho L / A using surface resistivity, or incorrectly averaging the conductivity.

Students must recognize that the medium acts as a series of infinitesimal resistors, requiring the integration of the resistivity function ρ(z)\rho(z) over the depth of the pit.

Additionally, it tests the crucial unit conversion of concentration from M (mol/L) to SI units (mol/m3^3) when calculating electrolytic conductivity, seamlessly integrating electrochemistry with calculus.

Quick Facts About This Question

Question Information

SubjectChemistry
ChapterElectrochemistry - Class 12
ConceptCorrosion as Electrochemical Process
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree