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Question #44801

Difficulty: 8/10 | 🟢 Free

The Question

Consider the acid-catalyzed hydrolysis of a Schiff base (\ceS\ce{S}) in an aqueous buffer at 298 K, which proceeds via the following mechanism: \ceS+H+<=>[Ka]SH+(Fast equilibrium)\ce{S + H+ <=>[K_a] SH+} \quad \text{(Fast equilibrium)} \ceSH++H2O−>[k2]Products(Slow, rate-determining)\ce{SH+ + H2O ->[k_2] Products} \quad \text{(Slow, rate-determining)} where KaK_a is the acid dissociation constant of the protonated imine (\ceSH+\ce{SH+}), given as 1.0×10−5 M1.0 \times 10^{-5} \text{ M}. The reaction follows pseudo-first order kinetics with respect to the total substrate concentration [\ceS]total[\ce{S}]_{total}, with an observed rate constant kobsk_{obs}. At a buffer pH of 5.0, kobs=6.0×10−4 s−1k_{obs} = 6.0 \times 10^{-4} \text{ s}^{-1}. Assuming the mechanism remains unchanged, what is the value of kobsk_{obs} at a buffer pH of 4.30? (Given: log⁡2=0.30\log 2 = 0.30)

Options

  • A.

    1.0×10−3 s−11.0 \times 10^{-3} \text{ s}^{-1}

  • B.

    3.0×10−3 s−13.0 \times 10^{-3} \text{ s}^{-1}

  • C.

    2.0×10−4 s−12.0 \times 10^{-4} \text{ s}^{-1}

  • D.

    8.0×10−4 s−18.0 \times 10^{-4} \text{ s}^{-1}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Mechanism_Trap

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Concepts Behind This Question

Pseudo-First Order Kinetics|Schiff Base pH Dependence|Steady State Approximation

Why This Question Is Tricky

Common Mistakes

This problem tests the student's ability to move beyond the rote assumption that acid-catalyzed pseudo-first order rate constants (kobsk_{obs}) are directly proportional to [\ceH+][\ce{H+}].

In the hydrolysis of Schiff bases, the substrate itself acts as a weak base.

The active reacting species is the protonated imine (\ceSH+\ce{SH+}).

As pH drops, the equilibrium shifts, and the concentration of \ceSH+\ce{SH+} saturates as it approaches [\ceS]total[\ce{S}]_{total}.

Failing to account for this equilibrium partitioning leads to the erroneous assumption of a linear dependence of rate on [\ceH+][\ce{H+}], trapping students into simply multiplying the rate by the factor of [\ceH+][\ce{H+}] increase (Option B), or incorrectly assuming the unprotonated species is the reactive one (Option C).

Quick Facts About This Question

Question Information

SubjectChemistry
ChapterChemical Kinetics - Class 12
ConceptPseudo-First Order Kinetics
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree