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Question #44822

Difficulty: 8/10 | 🟢 Free

The Question

In aqueous phase kinetics, the protonation of a highly sterically hindered amine, \ceB(aq)\ce{B(aq)}, is gated by the shedding of its primary hydration shell before an effective collision with \ceH+\ce{H+} can occur. The reaction proceeds via the following mechanism:

Step 1: \ceB(aq)<=>[k1][k−1]B∗(aq)\ce{B(aq) <=>[k_1][k_{-1}] B^*(aq)} (Formation of reactive desolvated intermediate) Step 2: \ceB∗(aq)+H+(aq)−>[k2]BH+(aq)\ce{B^*(aq) + H+(aq) ->[k_2] BH+(aq)}

At 298 K298\text{ K}, the rate constants are k1=2.0×103 s−1k_1 = 2.0 \times 10^3 \text{ s}^{-1}, k−1=1.0×108 s−1k_{-1} = 1.0 \times 10^8 \text{ s}^{-1}, and k2=4.0×109 M−1s−1k_2 = 4.0 \times 10^9 \text{ M}^{-1}\text{s}^{-1}.

Calculate the initial rate of formation of \ceBH+(aq)\ce{BH+(aq)} when the initial concentration of the amine is [\ceB]0=5.0×10−4 M[\ce{B}]_0 = 5.0 \times 10^{-4} \text{ M} and the solution is buffered at pH=1.125\text{pH} = 1.125 (Assume [\ceH+]=0.075 M[\ce{H+}] = 0.075 \text{ M}).

Options

  • A.

    0.75 M s−10.75 \text{ M s}^{-1}

  • B.

    3.0 M s−13.0 \text{ M s}^{-1}

  • C.

    1.0 M s−11.0 \text{ M s}^{-1}

  • D.

    1.5×105 M s−11.5 \times 10^5 \text{ M s}^{-1}

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Explanation

How the Examiner Thinks

Exception_Exposure

Learn to identify edge cases and boundary exceptions that JEE examiners hide in math problems.

Concepts Behind This Question

Collision Frequency vs. Effective Collisions|Basicity-Solvation Competition

Why This Question Is Tricky

Common Mistakes

Students often assume aqueous protonation follows simple second-order kinetics (the pre-equilibrium assumption, where k−1≫k2[\ceH+]k_{-1} \gg k_2[\ce{H+}]) or gas-phase collision theory.

However, for sterically hindered amines, the desolvation step creates a kinetic bottleneck.

At high [\ceH+][\ce{H+}], the rate of protonation (k2[\ceH+]k_2[\ce{H+}]) becomes comparable to or exceeds the rate of resolvation (k−1k_{-1}), shifting the reaction away from first-order dependence on [\ceH+][\ce{H+}].

Failing to apply the Steady-State Approximation leads to overestimating the rate by assuming a pre-equilibrium that doesn't exist (Option B), assuming purely zero-order dependence on acid (Option C), or ignoring the solvent cage entirely (Option D).

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Question Information

SubjectChemistry
ChapterChemical Kinetics - Class 12
ConceptCollision Frequency vs. Effective Collisions
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree