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Question #44834
The Question
A gaseous reactant \ce{A(g)} is continuously bubbled into an ideal solvent at a constant partial pressure of . The dissolved gas undergoes a second-order dimerization reaction: The temperature coefficient of the intrinsic rate constant for a rise from to is exactly . The standard enthalpy of dissolution of \ce{A(g)} in the solvent is . Assuming both the activation energy () and enthalpy of dissolution are temperature-independent, determine the observed temperature coefficient () for the overall rate of formation of \ce{A2(aq)}. (Given: , )
Options
- A.
- B.
- C.
- D.
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Exception_Exposure
Learn to identify edge cases and boundary exceptions that JEE examiners hide in math problems.
Concepts Behind This Question
Temperature Coefficient (Q10)|Henry’s Law Constant (Kh) Trends
Why This Question Is Tricky
Common Mistakes
This problem tests the interplay between Arrhenius kinetics and the thermodynamics of gas solubility (Henry's Law).
Students often blindly apply the temperature coefficient to the overall reaction, forgetting that the concentration of a dissolved gas decreases with temperature due to its exothermic dissolution ().
Furthermore, the trap involves the stoichiometric coefficient in the rate law (second-order), which doubles the exponential contribution of the solubility term, perfectly canceling the intrinsic activation energy and creating a temperature-independent reaction rate ().
Quick Facts About This Question
Question Information
| Subject | Chemistry |
| Chapter | Chemical Kinetics - Class 12 |
| Concept | Temperature Coefficient (Q10) |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |