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Question #44855
The Question
A 3d transition metal exhibits a positive standard reduction potential at because its hydration enthalpy fails to compensate for the sum of its atomization and ionization enthalpies. When an aqueous solution of is treated with excess , a soluble coordination complex and a toxic gas are formed. Separately, when is treated with excess , a precipitate and a brown solution containing species are formed.
Determine the value of the expression: Where: = Coordination number of the central metal in complex = Number of unpaired electrons in the central metal of complex = Oxidation state of in precipitate = Atomicity (total number of atoms per molecule) of gas
Options
- A.
6
- B.
8
- C.
10
- D.
12
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Exception_Exposure
Learn to identify edge cases and boundary exceptions that JEE examiners hide in math problems.
Concepts Behind This Question
Variable Oxidation State Stability|Electrode Potential Dependencies|Standard Electrode Potential Sign Conventions
Why This Question Is Tricky
Common Mistakes
The question tests the 'Hidden Oxidation State' trap and the thermodynamic anomalies of the 3d series.
Students often assume forms simple substitution complexes like or precipitates as .
However, and act as reducing agents, driving to due to the extreme stability of the resulting species (high formation constant of and high lattice energy of ).
The positive context serves as the initial identifier, reinforcing the Born-Haber cycle exception where hydration energy cannot overcome atomization and ionization energies.
Quick Facts About This Question
Question Information
| Subject | Chemistry |
| Chapter | D and F Block Elements - Class 12 |
| Concept | Variable Oxidation State Stability |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |