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Question #44864
The Question
The hypothetical tetrahedral complex () exhibits a high-spin configuration with a crystal field splitting energy and a pairing energy . For the isostructural () complex, the lanthanoid contraction results in nearly identical ionic radii. However, due to the greater radial extension of the 5d orbitals, for the Os complex is exactly 50% larger than that of the Ru complex, while its pairing energy decreases to . Calculate the expected spin-only magnetic moment () and the Crystal Field Stabilization Energy (CFSE, excluding pairing energy) for the complex.
Options
- A.
- B.
- C.
- D.
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Exception_Exposure
Learn to identify edge cases and boundary exceptions that JEE examiners hide in math problems.
Concepts Behind This Question
Lanthanoid Contraction cause|Tetrahedral Splitting Patterns
Why This Question Is Tricky
Common Mistakes
This problem targets the rote-memorized rule that 'tetrahedral complexes are always high-spin because '.
Students often fall into the trap of assuming that because the Lanthanoid Contraction makes 4d and 5d ionic radii nearly identical, their crystal field splitting energies must also be identical (leading to Distractor C).
The hidden variable is the relativistic radial expansion of 5d orbitals, which significantly increases covalency and , while the larger diffuse orbitals simultaneously lower the pairing energy .
This unique combination allows 5d elements to form low-spin tetrahedral complexes, completely flipping the expected high-spin configuration to .
Distractor D catches students who incorrectly apply octahedral splitting rules ( lower, higher) to a tetrahedral geometry.
Quick Facts About This Question
Question Information
| Subject | Chemistry |
| Chapter | D and F Block Elements - Class 12 |
| Concept | Lanthanoid Contraction cause |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |