Before You Begin
Question #44881
The Question
An aqueous solution of is electrolyzed at and using a Platinum anode and a Palladium () cathode. The mass of the Palladium cathode is . A constant current of is passed through the cell for . During the electrolysis, the Palladium cathode absorbs atomic hydrogen to form an interstitial hydride with the limiting composition before any hydrogen gas is evolved. Assuming current efficiency for the reduction of and that the cathode reaches its maximum hydrogen absorption capacity, what is the volume of evolved at the cathode?\n\n(Given: Atomic mass of , , Molar volume of an ideal gas at and )
Options
- A.
1.568 L
- B.
2.240 L
- C.
0.896 L
- D.
1.120 L
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Numerical_Precision
Improve calculation stamina and avoid rounding errors in high-stakes competitive examinations.
Concepts Behind This Question
Interstital Compound Formation|Electrolysis Product Prediction
Why This Question Is Tricky
Common Mistakes
This problem tests the intersection of Faraday's Laws of Electrolysis and solid-state chemistry (interstitial compounds).
The 'Textbook Rule' assumes 100% of the cathodic current yields H2(g).
The 'Hidden Variable' is the kinetic partitioning of adsorbed hydrogen (H_ads) into the Palladium lattice to form a non-stoichiometric interstitial hydride (PdH_x) before Volmer-Tafel recombination into H2(g) occurs.
Students commonly fall into the trap of calculating the theoretical Faradaic yield of H2 gas (2.240 L, Option B) without subtracting the moles of atomic hydrogen occluded by the cathode.
Another trap (Option C) involves confusing the stoichiometry of the hydride, erroneously subtracting 0.06 mol of H2 molecules instead of atomic H.
Option D is the volume of O2 gas evolved at the anode.
Quick Facts About This Question
Question Information
| Subject | Chemistry |
| Chapter | D and F Block Elements - Class 12 |
| Concept | Interstital Compound Formation |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |