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Question #44881

Difficulty: 8/10 | 🟢 Free

The Question

An aqueous solution of 0.1 M H2SO40.1 \text{ M } H_2SO_4 is electrolyzed at 273 K273 \text{ K} and 1 atm1 \text{ atm} using a Platinum anode and a Palladium (PdPd) cathode. The mass of the Palladium cathode is 10.64 g10.64 \text{ g}. A constant current of 9.65 A9.65 \text{ A} is passed through the cell for 2000 s2000 \text{ s}. During the electrolysis, the Palladium cathode absorbs atomic hydrogen to form an interstitial hydride with the limiting composition PdH0.60PdH_{0.60} before any hydrogen gas is evolved. Assuming 100%100\% current efficiency for the reduction of H+H^+ and that the cathode reaches its maximum hydrogen absorption capacity, what is the volume of H2(g)H_2(g) evolved at the cathode?\n\n(Given: Atomic mass of Pd=106.4 g/molPd = 106.4 \text{ g/mol}, 1 F=96500 C/mol1 \text{ F} = 96500 \text{ C/mol}, Molar volume of an ideal gas at 273 K273 \text{ K} and 1 atm=22.4 L/mol1 \text{ atm} = 22.4 \text{ L/mol})

Options

  • A.

    1.568 L

  • B.

    2.240 L

  • C.

    0.896 L

  • D.

    1.120 L

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Numerical_Precision

Improve calculation stamina and avoid rounding errors in high-stakes competitive examinations.

Concepts Behind This Question

Interstital Compound Formation|Electrolysis Product Prediction

Why This Question Is Tricky

Common Mistakes

This problem tests the intersection of Faraday's Laws of Electrolysis and solid-state chemistry (interstitial compounds).

The 'Textbook Rule' assumes 100% of the cathodic current yields H2(g).

The 'Hidden Variable' is the kinetic partitioning of adsorbed hydrogen (H_ads) into the Palladium lattice to form a non-stoichiometric interstitial hydride (PdH_x) before Volmer-Tafel recombination into H2(g) occurs.

Students commonly fall into the trap of calculating the theoretical Faradaic yield of H2 gas (2.240 L, Option B) without subtracting the moles of atomic hydrogen occluded by the cathode.

Another trap (Option C) involves confusing the stoichiometry of the hydride, erroneously subtracting 0.06 mol of H2 molecules instead of atomic H.

Option D is the volume of O2 gas evolved at the anode.

Quick Facts About This Question

Question Information

SubjectChemistry
ChapterD and F Block Elements - Class 12
ConceptInterstital Compound Formation
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree