Before You Begin
Question #45009
The Question
A galvanic cell is constructed at with the following cell representation:
The standard reduction potentials are and . Initially, the cell operates spontaneously. A ligand is then added to the cathode compartment, which selectively forms the highly stable complex with (Formation constant ). The concentration of free is maintained at , and the volume change is negligible.
What is the magnitude of the new cell potential, and what is the spontaneous cell reaction after the addition of the ligand? (Assume )
Options
- A.
, Disproportionation of \ce{Sn^{2+}}
- B.
, Comproportionation of \ce{Sn} and \ce{Sn^{4+}}
- C.
, Disproportionation of \ce{Sn^{2+}}
- D.
, Comproportionation of \ce{Sn} and \ce{Sn^{4+}}
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Numerical_Precision
Improve calculation stamina and avoid rounding errors in high-stakes competitive examinations.
Concepts Behind This Question
Comproportionation Reversibility|Concentration Cells|Standard State Conditions
Why This Question Is Tricky
Common Mistakes
This problem tests the Nernstian shift in a concentration/complexation cell.
Students must calculate the drastically reduced free Sn(IV) concentration due to complexation, which shifts the cathode potential from +0.15 V to -0.33 V.
The hidden trap lies in interpreting the resulting negative cell potential (E_cell = -0.19 V).
A negative potential indicates that the original spontaneous reaction (comproportionation of Sn and Sn(IV)) has reversed.
Students who only calculate the magnitude will incorrectly choose Option B, failing to recognize that the new spontaneous process is the disproportionation of Sn(II).
Quick Facts About This Question
Question Information
| Subject | Chemistry |
| Chapter | Redox Reactions - Class 11 Part 2 |
| Concept | Comproportionation Reversibility |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |