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Question #45015

Difficulty: 8/10 | 🟢 Free

The Question

An electrochemical cell is constructed at 298 K using two Nickel half-cells. Compartment A consists of a \ceNi(s)\ce{Ni(s)} electrode immersed in a solution containing 0.10 M \ce[NiCl4]2−0.10\text{ M } \ce{[NiCl4]^{2-}} and 1.0 M \ceCl−1.0\text{ M } \ce{Cl-}. Compartment B consists of a \ceNi(s)\ce{Ni(s)} electrode immersed in a solution containing 0.01 M \ce[Ni(CN)4]2−0.01\text{ M } \ce{[Ni(CN)4]^{2-}} and 0.10 M \ceCN−0.10\text{ M } \ce{CN-}. The overall formation constants are β4(\ce[NiCl4]2−)=102\beta_4(\ce{[NiCl4]^{2-}}) = 10^2 and β4(\ce[Ni(CN)4]2−)=1030\beta_4(\ce{[Ni(CN)4]^{2-}}) = 10^{30}. Assume 2.303RTF=0.06 V\frac{2.303 RT}{F} = 0.06\text{ V}. Determine the spontaneous EMF of the cell, and identify the coordination geometry and hybridization of the nickel complex present in the \textbf{anodic} compartment.

Options

  • A.

    0.75 V, Square Planar (dsp2dsp^2)

  • B.

    0.84 V, Square Planar (dsp2dsp^2)

  • C.

    0.75 V, Tetrahedral (sp3sp^3)

  • D.

    0.84 V, Tetrahedral (sp3sp^3)

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Exception_Exposure

Learn to identify edge cases and boundary exceptions that JEE examiners hide in math problems.

Concepts Behind This Question

Half-Reaction Media Sensitivity|Complex Ion Oxidation States|Valence Bond Theory Hybridization

Why This Question Is Tricky

Common Mistakes

This problem tests the synergy between Electrochemistry and Coordination Chemistry.

The primary trap is calculating the standard EMF (0.840.84 V) while ignoring the Nernstian concentration shifts, which leads to incorrect option B.

Furthermore, students must correctly identify the anode by comparing the actual oxidation potentials (EoxE_{ox}), not just assuming Compartment A is the anode.

Finally, it tests the application of Valence Bond Theory/Crystal Field Theory: recognizing that the massive thermodynamic stability (β4=1030\beta_4 = 10^{30}) in the anodic compartment is driven by the strong field nature of \ceCN−\ce{CN-}, which forces a transition from the typical sp3sp^3 (tetrahedral) geometry of weak field d8d^8 complexes to a dsp2dsp^2 (square planar) geometry.

Quick Facts About This Question

Question Information

SubjectChemistry
ChapterRedox Reactions - Class 11 Part 2
ConceptHalf-Reaction Media Sensitivity
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree