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Question #45020

Difficulty: 8/10 | 🟢 Free

The Question

A hydrogen-oxygen fuel cell operates at 300 K300 \text{ K} with non-standard partial pressures: P\ceH2=10 barP_{\ce{H2}} = 10 \text{ bar} and P\ceO2=100 barP_{\ce{O2}} = 100 \text{ bar}. The standard enthalpy of formation of liquid water is ΔHf∘(\ceH2O,l)=−300 kJ mol−1\Delta H^\circ_f(\ce{H2O}, l) = -300 \text{ kJ mol}^{-1}. The absolute molar entropies at 300 K300 \text{ K} are S∘(\ceH2,g)=150 J K−1mol−1S^\circ(\ce{H2}, g) = 150 \text{ J K}^{-1}\text{mol}^{-1}, S∘(\ceO2,g)=300 J K−1mol−1S^\circ(\ce{O2}, g) = 300 \text{ J K}^{-1}\text{mol}^{-1}, and S∘(\ceH2O,l)=60 J K−1mol−1S^\circ(\ce{H2O}, l) = 60 \text{ J K}^{-1}\text{mol}^{-1}.

Assume Faraday's constant F=100,000 C mol−1F = 100,000 \text{ C mol}^{-1} and the Nernst factor 2.303RTF=0.06 V\frac{2.303 RT}{F} = 0.06 \text{ V} at 300 K300 \text{ K}.

Determine the operating cell potential (EcellE_{\text{cell}}) and the thermodynamic efficiency (η=ΔGoperatingΔH∘×100\eta = \frac{\Delta G_{\text{operating}}}{\Delta H^\circ} \times 100) of the fuel cell under these conditions.

Options

  • A.

    1.20 V,80%1.20 \text{ V}, 80\%

  • B.

    1.23 V,82%1.23 \text{ V}, 82\%

  • C.

    1.14 V,76%1.14 \text{ V}, 76\%

  • D.

    0.975 V,65%0.975 \text{ V}, 65\%

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Numerical_Precision

Improve calculation stamina and avoid rounding errors in high-stakes competitive examinations.

Concepts Behind This Question

Nernstian Redox Equilibrium|Fuel Cell Efficiency|Stoichiometric Coefficient Division|Third Law Application

Why This Question Is Tricky

Common Mistakes

This problem tests the rigorous integration of Thermodynamics and Electrochemistry.

The primary trap (Option B) catches students who fail to apply the stoichiometric coefficient of 1/2 to the oxygen partial pressure in the reaction quotient Q, leading to an incorrect Nernst potential.

The secondary trap (Option D) targets the misapplication of the Third Law of Thermodynamics, where students ignore stoichiometry when calculating standard entropy change.

Finally, it reinforces that fuel cell efficiency must be calculated using the operating Gibbs free energy, not the standard Gibbs free energy (Option C).

Quick Facts About This Question

Question Information

SubjectChemistry
ChapterRedox Reactions - Class 11 Part 2
ConceptNernstian Redox Equilibrium
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree