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Question #45021
The Question
Consider the following electrochemical cell at :
Given the following thermodynamic data:
Determine the initial cell potential () and the spontaneous direction of electron flow in the external circuit.
Options
- A.
, Right to Left
- B.
, Left to Right
- C.
, Right to Left
- D.
, Right to Left
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Exception_Exposure
Learn to identify edge cases and boundary exceptions that JEE examiners hide in math problems.
Concepts Behind This Question
Electrode Potential Sign Conventions|Metal Activity Series Logic|Concentration Cells
Why This Question Is Tricky
Common Mistakes
This question tests the thermodynamic principles of concentration cells and the Nernst equation.
The primary trap is the 'Hidden Variable' of : students often erroneously substitute the highly negative standard reduction potential of the active metal () into the Nernst equation instead of , leading to Distractor D.
Additionally, it tests the 'Chemical Exception' where a cell diagram is written such that the cathodic concentration is lower than the anodic concentration, resulting in a negative .
Students must recognize that a negative potential implies the spontaneous electron flow is opposite to the standard left-to-right convention.
Quick Facts About This Question
Question Information
| Subject | Chemistry |
| Chapter | Redox Reactions - Class 11 Part 2 |
| Concept | Electrode Potential Sign Conventions |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |