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Question #45044

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The Question

Aniline is subjected to direct nitration using a standard nitrating mixture (conc. \ceHNO3\ce{HNO3} and conc. \ceH2SO4\ce{H2SO4}) at 288 K288\text{ K}. Surprisingly, alongside the expected ortho and para derivatives, a significant amount of the meta-isomer is formed. Identify the approximate percentage yield of the meta-isomer, the hybridization of the nitrogen atom in the reactive intermediate responsible for this meta-direction, and the dominant electronic effect exerted by this modified substituent.

Options

  • A.

    47%, sp3sp^3, −I-I effect

  • B.

    51%, sp2sp^2, +M+M effect

  • C.

    47%, sp2sp^2, −M-M effect

  • D.

    2%, sp3sp^3, +I+I effect

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Explanation

How the Examiner Thinks

Exception_Exposure

Learn to identify edge cases and boundary exceptions that JEE examiners hide in math problems.

Concepts Behind This Question

Hybridization and Geometry|Aniline Resonance Pitfalls|Azo Coupling Regioselectivity

Why This Question Is Tricky

Common Mistakes

This question tests the 'Chemical Exception' of aniline's reactivity in strongly acidic media.

Students often blindly apply the rule that −\ceNH2-\ce{NH2} is a strong ortho/para directing activator due to its +M+M effect.

The trap lies in failing to account for the acid-base thermodynamics that precede the Electrophilic Aromatic Substitution (EAS).

In the nitrating mixture, aniline is protonated to the anilinium ion.

This protonation fundamentally alters the nitrogen's geometry from an sp2sp^2-like state (capable of resonance overlap) to a strictly sp3sp^3 tetrahedral state.

The sequestration of the lone pair nullifies the +M+M effect, leaving only a strong −I-I effect, which converts the substituent into a meta-directing deactivator, yielding an anomalously high 47% of the meta-isomer.

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Question Information

SubjectChemistry
ChapterOrganic Chemistry – Some Basic Principles and Techniques - Class 11 Part 2
ConceptHybridization and Geometry
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree