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Question #45081
The Question
Consider the highly sterically hindered alkene, 2,2,5-trimethyl-3-phenyl-4-(2,4,6-trimethylphenyl)hex-3-ene. Isomer of this compound is synthesized such that the phenyl group and the group are positioned on the same side of the double bond axis (in terms of connectivity). Due to severe B-strain, the bond is significantly twisted out of planarity.
Let be the formal Cahn-Ingold-Prelog (CIP) stereodescriptor value for Isomer (Assign for , for , and if the nomenclature is formally invalid due to the loss of planarity). Let be the total number of formally hybridized carbon atoms in the molecule. Let be the number of planes of symmetry in its most stable twisted conformation at 298 K.
Calculate the value of .
Options
- A.
14
- B.
15
- C.
16
- D.
18
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Mechanism_Trap
Don't get tricked by the process! Learn the mechanical traps used in competitive exam questions.
Concepts Behind This Question
Cahn-Ingold-Prelog (CIP) Priority|Steric Hindrance (B-Strain)
Why This Question Is Tricky
Common Mistakes
This question tests three distinct traps.
First, the 'Chemical Exception' trap: students often assume that severe steric twisting (B-strain) invalidates E/Z nomenclature because the molecule is no longer planar ().
However, IUPAC CIP rules are topological, so the descriptor remains formally valid.
Second, a common CIP trap: confusing steric bulk with atomic number priority.
Students might incorrectly assign tert-butyl a higher priority than phenyl due to its size, leading to a false assignment ().
Third, it tests the ability to identify centers and 3D symmetry in sterically hindered, non-planar systems.
Quick Facts About This Question
Question Information
| Subject | Chemistry |
| Chapter | Organic Chemistry – Some Basic Principles and Techniques - Class 11 Part 2 |
| Concept | Cahn-Ingold-Prelog (CIP) Priority |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |