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Question #45294
The Question
During the completion of Meiosis II in a human secondary oocyte, a highly specific chemical inhibitor blocks the activity of the Anaphase Promoting Complex (APC). If fertilization proceeds, which of the following represents the most accurate cytological consequence and its resulting genetic condition in the zygote?
Options
- A.
Failure of homologous chromosome segregation, resulting in an aneuploid zygote (2n+1 or 2n-1).
- B.
Failure of centromere splitting and sister chromatid separation, resulting in an aneuploid zygote (2n+1 or 2n-1).
- C.
Premature cleavage of cohesin proteins, leading to structural chromosomal aberrations in a diploid zygote (2n).
- D.
Failure of cytokinesis following normal karyokinesis, resulting in a polyploid zygote (3n).
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Regulatory_Failure
Understand how NOT, EXCEPT, and logical constraints are used to manipulate exam results.
Concepts Behind This Question
APC|Cohesin|Secondary_Oocyte|Meiotic_Arrest_Points
Why This Question Is Tricky
Common Mistakes
Conceptual Pivot: Distinguishing between the segregation events of Meiosis I (homologous chromosomes) and Meiosis II (sister chromatids via centromere splitting).
Common Misconception: Students frequently confuse the cytological cause of Aneuploidy (failure of chromatid segregation/non-disjunction) with Polyploidy (failure of cytokinesis).
Quick Facts About This Question
Question Information
| Subject | Biology |
| Chapter | Cell Cycle and Cell Division - Class 11 |
| Concept | Anaphase Promotion Complex (APC) |
| Difficulty | 8 |
| Cognitive Load | 5 |
| Target Solve Time | 120 sec |
| Access | Free |