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Question #46249
The Question
In certain angiosperms, the evolution of zygomorphic flowers optimizes specific pollinator visits. Suppose the gene controlling this bilateral symmetry is tightly linked to a locus that dictates the transition from a hermaphroditic to a dioecious state. Based on the Chromosomal Theory of Inheritance and the concept of linkage, which of the following statements is NOT correct regarding the evolutionary consequences of this genetic architecture?
Options
- A.
The physical association of these genes on the same chromosome restricts the independent assortment of floral symmetry and sexuality.
- B.
The population's phenotypic plasticity to independently adapt its floral symmetry and reproductive strategy is severely limited.
- C.
A high frequency of recombinant phenotypes exhibiting novel combinations of symmetry and sexuality will rapidly emerge to maximize reproductive success.
- D.
The specific traits for zygomorphy and the sexual state will tend to co-segregate and be inherited together as a single linkage group.
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Comparative_Analysis
Sharpen your ability to evaluate multiple scenarios and distinguish between competing potential answers.
Concepts Behind This Question
Actinomorphy|Zygomorphy|Chromosomal Theory of Inheritance
Why This Question Is Tricky
Common Mistakes
Conceptual Pivot: Students often assume that evolutionary pressure automatically generates high variation (recombinants) for adaptation.
However, they must synthesize this with the Mendelian exception of 'Linkage'.
The trap lies in confusing the evolutionary 'need' for variation with the genetic 'constraint' imposed by tightly linked genes, which inherently prevents high recombination frequencies regardless of selective pressure.
Quick Facts About This Question
Question Information
| Subject | Biology |
| Chapter | Morphology of Flowering Plants - Class 11 |
| Concept | Flower Symmetry and Sexuality |
| Difficulty | 8 |
| Cognitive Load | 5 |
| Target Solve Time | 120 sec |
| Access | Free |