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Question #46785

Difficulty: 8/10 | 🟢 Free

The Question

An E. coli culture, grown for several generations in a medium containing 15N (heavy nitrogen), is transferred to a normal 14N medium. Simultaneously, a temperature-sensitive mutation is activated that completely abolishes the recognition of the 'ori' sequence by initiator proteins. After 20 minutes (one normal generation time), the DNA is extracted and subjected to CsCl density gradient centrifugation. Which of the following correctly describes the expected banding pattern and the primary biochemical reason?

Options

  • A.

    A single intermediate density band (14N-15N); DNA Polymerase III bypasses the 'ori' sequence and utilizes random 3'-OH ends to complete semi-conservative replication.

  • B.

    A single heavy density band (15N-15N); failure to form the pre-replication complex prevents template unwinding, depriving DNA Polymerase of the required 3'-OH ends from RNA primers.

  • C.

    Two bands, one heavy (15N-15N) and one light (14N-14N); the mutation forces the replication machinery to adopt a conservative mode of replication to bypass the 'ori' defect.

  • D.

    A single heavy density band (15N-15N); the replication fork forms but immediately collapses because DNA Polymerase III lacks 3' to 5' exonuclease activity in the mutant.

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Regulatory_Failure

Understand how NOT, EXCEPT, and logical constraints are used to manipulate exam results.

Concepts Behind This Question

DNA Polymerase Directionality|Ori Sequence Stringency|Meselson-Stahl Density Gradient

Why This Question Is Tricky

Common Mistakes

Conceptual Pivot: Students often rote-memorize the Meselson-Stahl experiment results (20 mins = 100% intermediate band) without integrating the biochemical prerequisites of DNA replication.

This question traps students who fail to realize that without 'ori' recognition, the entire downstream cascade (helicase loading -> primer synthesis -> 3'-OH availability for DNA Pol III) fails.

Thus, replication does not even begin, leaving the original heavy DNA intact.

Quick Facts About This Question

Question Information

SubjectBiology
ChapterBiomolecules - Class 11
ConceptPeptide Bond Geometry
Difficulty8
Cognitive Load5
Target Solve Time120 sec
AccessFree