Start Learning Free

Before You Begin

Question #51348

Difficulty: 8/10 | 🟢 Free

The Question

Let AA and BB be 3×33 \times 3 real matrices satisfying the idempotent property X2=XX^2 = X (analogous to the set identity S∪S=SS \cup S = S). Suppose AB=BA=OAB = BA = O, det⁡(I−2A)=−1\det(I - 2A) = -1, and det⁡(I−2B)=1\det(I - 2B) = 1. If BB is a non-null matrix, find the value of log⁡2(det⁡(A−B+3I))\log_2(\det(A - B + 3I)).

Options

  • A.

    3

  • B.

    4

  • C.

    5

  • D.

    6

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Monster

Ultra-high difficulty questions designed to test your limit, stamina, and deep conceptual understanding.

Concepts Behind This Question

Set Identity Laws|Idempotent and Involutory Properties|Singular vs Non-Singular Matrices|Properties of Transpose Determinant

Why This Question Is Tricky

Examiner Levers

Concept Bridge

Cross-chapter synthesis (e.g., using Logarithms in Electrochemistry).

Difficulty Boost : +5

Common Mistakes

This question tests the synthesis of idempotent matrix properties and simultaneous diagonalizability, mapping set identity laws (X∪X=XX \cup X = X) to matrix algebra (X2=XX^2 = X).

The primary trap lies in the determinant conditions: students often incorrectly assume that if A2=AA^2 = A, then det⁡(A)=1\det(A) = 1 (ignoring the singular case det⁡(A)=0\det(A) = 0), which would falsely imply A=IA = I and B=OB = O.

Furthermore, it tests the involutory nature of I−2AI - 2A.

By forcing students to deduce the exact eigenvalue spectrums (λA={1,0,0}\lambda_A=\{1,0,0\} and λB={0,1,1}\lambda_B=\{0,1,1\}) and use AB=OAB=O to prove A+B=IA+B=I, it punishes those who attempt to blindly expand the determinant without analyzing the underlying eigenbasis.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterSets - Class 11
ConceptSet Identity Laws
Difficulty8
Cognitive Load7
Target Solve Time170 sec
AccessFree