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Question #59875
The Question
Let be a discrete random variable taking values in the set . A student incorrectly assumes that is uniformly distributed over . Later, the true probability mass function is found to be for , where is a constant. Let be the true variance of . The value of is:
Options
- A.
441
- B.
369
- C.
600
- D.
450
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Monster
Ultra-high difficulty questions designed to test your limit, stamina, and deep conceptual understanding.
Concepts Behind This Question
Correction of Incorrect Mean/Variance|Probability Mass Function (PMF)|Equiprobable Outcomes
Why This Question Is Tricky
Examiner Levers
Concept Bridge
Cross-chapter synthesis (e.g., using Logarithms in Electrochemistry).
Difficulty Boost : +5Common Mistakes
This question tests the correction of a probability distribution by properly normalizing a given weight function.
The primary trap lies in the 'Equiprobable Outcomes' assumption, which students might incorrectly blend with the new PMF.
The secondary trap is the numerical distractor '369', which emerges exactly as the unnormalized sum of squares if the student reduces the probability ratios to 3:5:2 but forgets to divide by the sum of these weights (10).
This creates a false sense of confidence, leading them to select 369 instead of completing the full variance calculation.
Quick Facts About This Question
Question Information
| Subject | Mathematics |
| Chapter | Statistics - Class 11 |
| Concept | Correction of Incorrect Mean/Variance |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 170 sec |
| Access | Free |