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Question #76782

Difficulty: 8/10 | 🟢 Free

The Question

A semiconductor diode is used as a temperature sensor. When driven by a constant forward current, the voltage VV across the diode is given by the relation: V(T)=Eg(T)e−ηTV(T) = \frac{E_g(T)}{e} - \eta T where ee is the elementary charge, TT is the absolute temperature, and η=4.0×10−3 V/K\eta = 4.0 \times 10^{-3} \text{ V/K}. The band gap energy Eg(T)E_g(T) of the semiconductor varies with temperature as: Eg(T)=Eg0−αT2E_g(T) = E_{g0} - \alpha T^2 where Eg0=1.2 eVE_{g0} = 1.2 \text{ eV} and α=2.0×10−5 eV/K2\alpha = 2.0 \times 10^{-5} \text{ eV/K}^2. The diode voltage is measured using a digital voltmeter with a least count of ΔV=0.48 mV\Delta V = 0.48 \text{ mV}. What is the minimum temperature change ΔT\Delta T (the "blind spot") that this sensor can detect at an ambient temperature of T=300 KT = 300 \text{ K}?

Options

  • A.

    0.03 \text{ K}

  • B.

    0.06 \text{ K}

  • C.

    0.12 \text{ K}

  • D.

    0.048 \text{ K}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Multi-Concept_Bridge

Master problems that require linking physics and math concepts to solve complex competitive questions.

Concepts Behind This Question

Least Count and Resolution Limits|Energy Band Gap Temperature Dependency

Why This Question Is Tricky

Examiner Levers

Concept Bridge

Cross-chapter synthesis (e.g., using Logarithms in Electrochemistry).

Difficulty Boost : +5

Common Mistakes

This question tests the student's ability to synthesize semiconductor physics with experimental error analysis (least count).

The primary trap lies in treating the energy band gap EgE_g as a constant Eg0E_{g0} when differentiating the voltage function, which leads to an incorrect sensitivity of 4.0 mV/K4.0 \text{ mV/K} and a false blind spot of 0.12 K0.12 \text{ K}.

A secondary trap involves a sign error during differentiation, where students might subtract the magnitudes of the two thermal drift components instead of adding them, yielding 0.06 K0.06 \text{ K}.

Another common error is forgetting the factor of 2 when differentiating T2T^2, leading to 0.048 K0.048 \text{ K}.

The problem requires recognizing that the intrinsic thermal drift of the band gap significantly amplifies the diode's temperature sensitivity.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterUnits and Measurements - Class 11 Part 1
ConceptLeast Count and Resolution Limits
Difficulty8
Cognitive Load7
Target Solve Time170 sec
AccessFree