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Question #77724

Difficulty: 8/10 | 🟢 Free

The Question

A rigid, non-conducting thin rod of length L=4aL = 4a is placed along the positive x-axis with one end at the origin (0,0,0)(0,0,0). The rod carries a non-uniform linear charge density λ=cx2\lambda = c x^2, where cc is a positive constant with units of C⋅m−3\text{C}\cdot\text{m}^{-3} and xx is the distance from the origin. A point charge q0q_0 of mass mm is held stationary at the point (0,3a,0)(0, 3a, 0). A uniform magnetic field B⃗=B0k^\vec{B} = B_0 \hat{k} exists in the entire region. Determine the net initial force vector F⃗\vec{F} experienced by the point charge q0q_0 immediately after it is released. Assume the permittivity of free space is ϵ0\epsilon_0.

Options

  • A.

    q0ca4πϵ0[−45i^+(3ln⁡3−125)j^]\frac{q_0 c a}{4\pi\epsilon_0} \left[ -\frac{4}{5} \hat{i} + \left(3\ln 3 - \frac{12}{5}\right) \hat{j} \right]

  • B.

    q0ca4πϵ0[45i^+(ln⁡3−45)j^]\frac{q_0 c a}{4\pi\epsilon_0} \left[ \frac{4}{5} \hat{i} + \left(\ln 3 - \frac{4}{5}\right) \hat{j} \right]

  • C.

    q0ca4πϵ0[−45i^+3ln⁡3j^]\frac{q_0 c a}{4\pi\epsilon_0} \left[ -\frac{4}{5} \hat{i} + 3\ln 3 \hat{j} \right]

  • D.

    q0ca4πϵ0[−85i^+(3ln⁡3−125)j^]\frac{q_0 c a}{4\pi\epsilon_0} \left[ -\frac{8}{5} \hat{i} + \left(3\ln 3 - \frac{12}{5}\right) \hat{j} \right]

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Multi-Concept_Bridge

Master problems that require linking physics and math concepts to solve complex competitive questions.

Concepts Behind This Question

Dimensional Independence vs. Scalar/Vector Nature|Coulomb's Law Vector Form|Integration

Why This Question Is Tricky

Examiner Levers

Extraneous Data

Provides unnecessary variables (Red Herrings) to test conceptual focus.

Difficulty Boost : +3

Visualization Stress

Requires mental rotation or 3D mapping (Optics/Geometry/Vectors).

Difficulty Boost : +4

Concept Bridge

Cross-chapter synthesis (e.g., using Logarithms in Electrochemistry).

Difficulty Boost : +5

Common Mistakes

This problem tests the dimensional independence of vector components during the integration of a non-uniform spatial charge density, a frequent stumbling block in JEE Advanced Electrostatics.

Students often fall into the trap of scalar summation, ignoring the spatial orientation of the differential force vector dF⃗d\vec{F}.

By introducing λ=cx2\lambda = cx^2, the problem forces a rigorous vector projection where the x and y components require distinct integration techniques (algebraic substitution vs. trigonometric substitution).

A common mathematical trap is dropping the −cos⁡θ-\cos\theta term during the y-component integration, leading directly to Option C.

Additionally, the presence of the magnetic field acts as a conceptual red herring, testing whether students correctly apply the Lorentz force law to recognize that a stationary charge experiences zero magnetic force.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterUnits and Measurements - Class 11 Part 1
ConceptDimensional Independence vs. Scalar/Vector Nature
Difficulty8
Cognitive Load8
Target Solve Time180 sec
AccessFree