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Question #80902

Difficulty: 5/10 | 🟢 Free

The Question

An AC voltage source V(t)=V0sin⁡(ωt)V(t) = V_0 \sin(\omega t) is connected in series with a resistor of resistance RR, an inductor of inductance LL, and a parallel plate capacitor. The capacitor is initially filled with a solid dielectric. The dielectric is being withdrawn at a constant speed such that the capacitance decreases linearly with time as C(t)=C0−βtC(t) = C_0 - \beta t, where β>0\beta > 0 is a constant rate in F/s\text{F/s}. Assume that the observation time is sufficiently small such that βt≪C0\beta t \ll C_0, allowing C(t)C(t) to be approximated as C0C_0 in its magnitude, but its rate of change dCdt=−β\frac{dC}{dt} = -\beta remains significant. Determine the phase angle ϕ\phi by which the source voltage leads the current in the pseudo-steady state.

Options

  • A.

    tan⁡−1[ωL(β2+ω2C02)−ωC0R(β2+ω2C02)−β]\tan^{-1} \left[ \frac{\omega L (\beta^2 + \omega^2 C_0^2) - \omega C_0}{R (\beta^2 + \omega^2 C_0^2) - \beta} \right]

  • B.

    tan⁡−1[ωL(β2+ω2C02)−ωC0R(β2+ω2C02)+β]\tan^{-1} \left[ \frac{\omega L (\beta^2 + \omega^2 C_0^2) - \omega C_0}{R (\beta^2 + \omega^2 C_0^2) + \beta} \right]

  • C.

    tan⁡−1[ωL−(ωC0)−1R]\tan^{-1} \left[ \frac{\omega L - (\omega C_0)^{-1}}{R} \right]

  • D.

    tan⁡−1[ωL(β2+ω2C02)−βR(β2+ω2C02)−ωC0]\tan^{-1} \left[ \frac{\omega L (\beta^2 + \omega^2 C_0^2) - \beta}{R (\beta^2 + \omega^2 C_0^2) - \omega C_0} \right]

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Explanation

How the Examiner Thinks

Multi-Concept_Bridge

Master problems that require linking physics and math concepts to solve complex competitive questions.

Concepts Behind This Question

Phase Constant Determination|Phasor Rotation Convention|Bandwidth in RLC|Non-Uniform Dielectric Filling

Why This Question Is Tricky

Examiner Levers

Dimensional Analysis

Tests if the student verifies units/dimensions before selecting.

Difficulty Boost : +2

Common Mistakes

This question tests the fundamental definition of current in a capacitor, I=dq/dt=d(CV)/dtI = dq/dt = d(CV)/dt.

Students commonly misapply the steady-state AC reactance formula XC=1/(ωC)X_C = 1/(\omega C), ignoring the product rule expansion which introduces a V(dC/dt)V(dC/dt) term.

When the dielectric is withdrawn, the time-varying capacitance acts mathematically as a complex impedance with a negative real part (a negative resistance).

This physically reflects the mechanical work done by the external agent being converted into electrical energy, pumping power back into the circuit.

Failing to account for this non-autonomous nature of the differential equation leads to incorrect phase constant determinations, trapping students who rely solely on standard RLC formulas.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterOscillations - Class 11 Part 2
ConceptPhase Constant Determination
Difficulty5
Cognitive Load6
Target Solve Time140 sec
AccessFree