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Question #80902
The Question
An AC voltage source is connected in series with a resistor of resistance , an inductor of inductance , and a parallel plate capacitor. The capacitor is initially filled with a solid dielectric. The dielectric is being withdrawn at a constant speed such that the capacitance decreases linearly with time as , where is a constant rate in . Assume that the observation time is sufficiently small such that , allowing to be approximated as in its magnitude, but its rate of change remains significant. Determine the phase angle by which the source voltage leads the current in the pseudo-steady state.
Options
- A.
- B.
- C.
- D.
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Multi-Concept_Bridge
Master problems that require linking physics and math concepts to solve complex competitive questions.
Concepts Behind This Question
Phase Constant Determination|Phasor Rotation Convention|Bandwidth in RLC|Non-Uniform Dielectric Filling
Why This Question Is Tricky
Examiner Levers
Dimensional Analysis
Tests if the student verifies units/dimensions before selecting.
Difficulty Boost : +2Common Mistakes
This question tests the fundamental definition of current in a capacitor, .
Students commonly misapply the steady-state AC reactance formula , ignoring the product rule expansion which introduces a term.
When the dielectric is withdrawn, the time-varying capacitance acts mathematically as a complex impedance with a negative real part (a negative resistance).
This physically reflects the mechanical work done by the external agent being converted into electrical energy, pumping power back into the circuit.
Failing to account for this non-autonomous nature of the differential equation leads to incorrect phase constant determinations, trapping students who rely solely on standard RLC formulas.
Quick Facts About This Question
Question Information
| Subject | Physics |
| Chapter | Oscillations - Class 11 Part 2 |
| Concept | Phase Constant Determination |
| Difficulty | 5 |
| Cognitive Load | 6 |
| Target Solve Time | 140 sec |
| Access | Free |