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Question #83206

Difficulty: 5/10 | 🟢 Free

The Question

A quantity of n=3 molesn = 3 \text{ moles} of an ideal non-linear polyatomic gas with molar heat capacity at constant volume Cv=3RC_v = 3R undergoes a quasi-static cyclic process. The path of the cycle in the P−VP-V plane is given by the parametric equations P(t)=P0+αsin⁡(ωt)P(t) = P_0 + \alpha \sin(\omega t) and V(t)=V0+βcos⁡(ωt)V(t) = V_0 + \beta \cos(\omega t) for time t∈[0,2πω]t \in [0, \frac{2\pi}{\omega}]. The constants are given as P0=2×105 PaP_0 = 2 \times 10^5 \text{ Pa}, V0=0.05 m3V_0 = 0.05 \text{ m}^3, α=0.5×105 Pa\alpha = 0.5 \times 10^5 \text{ Pa}, and β=0.01 m3\beta = 0.01 \text{ m}^3. What is the net change in the total translational kinetic energy of the gas molecules over one complete cycle?

Options

  • A.

    0 J0 \text{ J}

  • B.

    500π J500\pi \text{ J}

  • C.

    750π J750\pi \text{ J}

  • D.

    1500π J1500\pi \text{ J}

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Multi-Concept_Bridge

Master problems that require linking physics and math concepts to solve complex competitive questions.

Concepts Behind This Question

Pressure-Kinetic Energy Relation|Cyclic Process Geometry|Integration

Why This Question Is Tricky

Examiner Levers

Extraneous Data

Provides unnecessary variables (Red Herrings) to test conceptual focus.

Difficulty Boost : +3

Common Mistakes

This question tests the fundamental distinction between state functions and path functions in thermodynamics.

Students often conflate the cyclic integral of work (∮PdV\oint P dV) or heat with the change in internal energy components.

By providing a complex parametric path and extraneous variables like CvC_v and the cycle's amplitudes, the problem baits students into calculating the area of the P−VP-V loop (yielding 500π J500\pi \text{ J}) or misapplying the pressure-kinetic energy relation as a differential flux (32∮PdV=750π J\frac{3}{2} \oint P dV = 750\pi \text{ J}).

The trap penalizes those who fail to recognize that translational kinetic energy, being strictly proportional to the state variables PP and VV, is a state function whose net change over any closed loop is identically zero.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterKinetic Theory - Class 11 Part 2
ConceptPressure-Kinetic Energy Relation
Difficulty5
Cognitive Load6
Target Solve Time150 sec
AccessFree