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Question #84402

Difficulty: 5/10 | 🟢 Free

The Question

A vertical, thermally conducting cylinder of cross-sectional area AA is closed at the bottom and fitted with a frictionless, airtight piston of mass MpM_p. The cylinder contains an ideal gas of total mass MgM_g and molar mass μ\mu. The entire system is maintained at a constant temperature TT. Due to the large height of the gas column, the hydrostatic pressure gradient within the gas cannot be ignored. The piston is slightly displaced downwards from its equilibrium position and released. Assuming the gas continuously maintains hydrostatic equilibrium and its kinetic energy is negligible during the motion, what is the angular frequency ω\omega of the resulting vertical oscillations?

(Given: Acceleration due to gravity is gg, Universal gas constant is RR, and the space above the piston is a vacuum)

Options

  • A.

    μg2RT(Mp+MgMg)\sqrt{\frac{\mu g^2}{R T} \left( \frac{M_p + M_g}{M_g} \right)}

  • B.

    μg2RT(MpMg)\sqrt{\frac{\mu g^2}{R T} \left( \frac{M_p}{M_g} \right)}

  • C.

    μg2RT(MpMp+Mg)\sqrt{\frac{\mu g^2}{R T} \left( \frac{M_p}{M_p + M_g} \right)}

  • D.

    μg2RT(MgMp)\sqrt{\frac{\mu g^2}{R T} \left( \frac{M_g}{M_p} \right)}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Intuition_Breaker

Train your brain to resist "obvious" answers that are designed to deceive your intuition.

Concepts Behind This Question

Ideal Gas Assumptions|Vertical Oscillations|Integration

Why This Question Is Tricky

Examiner Levers

Dimensional Analysis

Tests if the student verifies units/dimensions before selecting.

Difficulty Boost : +2

Common Mistakes

This question tests the student's ability to account for the gravitational potential energy of a gas column during vertical oscillations.

The primary trap lies in misapplying the ideal gas law by assuming a uniform pressure distribution (P=Mpg/AP = M_p g / A) and ignoring the work done against the gas's own weight.

Students typically calculate the spring constant as k=PA/hk = P A / h, which erroneously treats the gas as a massless spring.

By forcing the inclusion of the gas mass (MgM_g), the effective spring constant shifts to a coupled relation involving both the piston and the gas mass.

This requires integrating the hydrostatic pressure gradient to find the true restoring force, reflecting the change in the center of mass of the gas.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterKinetic Theory - Class 11 Part 2
ConceptIdeal Gas Assumptions
Difficulty5
Cognitive Load6
Target Solve Time140 sec
AccessFree