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Question #42133

Difficulty: 8/10 | 🟢 Free

The Question

An unconstrained isotropic solid block contains a spherical cavity of radius RR centered at the origin (0,0,0)(0,0,0). The block is subjected to a steady-state temperature distribution T(x,y,z)=T0+βxT(x,y,z) = T_0 + \beta x, where T0T_0 and β\beta are positive constants. The rigid body motion of the block is constrained such that the theoretical displacement and rotation at the origin are zero. If α\alpha is the coefficient of linear thermal expansion of the material, what is the displacement vector of the point on the cavity boundary originally located at (0,R,0)(0, R, 0)? (Assume αβR≪1\alpha \beta R \ll 1).

Options

  • A.

    −12αβR2i^-\frac{1}{2} \alpha \beta R^2 \hat{i}

  • B.

    12αβR2i^\frac{1}{2} \alpha \beta R^2 \hat{i}

  • C.

    αβR2j^\alpha \beta R^2 \hat{j}

  • D.

    0⃗\vec{0}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Intuition_Breaker

Train your brain to resist "obvious" answers that are designed to deceive your intuition.

Concepts Behind This Question

Expansion of Cavities in Solids|Superposition Principle|Small Angle Approximation

Why This Question Is Tricky

Common Mistakes

This question tests the student's understanding of thermal gradient-induced anisotropy and the superposition of displacement fields.

The lethal trap is the assumption that local thermal expansion depends only on the local temperature change.

Since the temperature at (0,R,0)(0, R, 0) is T0T_0 (meaning ΔT=0\Delta T = 0), most students will incorrectly conclude the point does not move (Option D), or they will assume the cavity expands radially (Option C).

However, thermal expansion is a cumulative, tensor-based deformation.

The expansion of the hotter region (x>0x>0) and contraction of the colder region (x<0x<0) forces the material at x=0x=0 to bow towards the colder side to maintain geometric compatibility (zero shear stress).

This causes the points on the y-axis to displace in the negative x-direction, demonstrating that the cavity undergoes non-conformal distortion rather than simple scalar scaling.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterThermal Properties of Matter - Class 11 Part 2
ConceptExpansion of Cavities in Solids
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree