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Question #42133
The Question
An unconstrained isotropic solid block contains a spherical cavity of radius centered at the origin . The block is subjected to a steady-state temperature distribution , where and are positive constants. The rigid body motion of the block is constrained such that the theoretical displacement and rotation at the origin are zero. If is the coefficient of linear thermal expansion of the material, what is the displacement vector of the point on the cavity boundary originally located at ? (Assume ).
Options
- A.
- B.
- C.
- D.
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Intuition_Breaker
Train your brain to resist "obvious" answers that are designed to deceive your intuition.
Concepts Behind This Question
Expansion of Cavities in Solids|Superposition Principle|Small Angle Approximation
Why This Question Is Tricky
Common Mistakes
This question tests the student's understanding of thermal gradient-induced anisotropy and the superposition of displacement fields.
The lethal trap is the assumption that local thermal expansion depends only on the local temperature change.
Since the temperature at is (meaning ), most students will incorrectly conclude the point does not move (Option D), or they will assume the cavity expands radially (Option C).
However, thermal expansion is a cumulative, tensor-based deformation.
The expansion of the hotter region () and contraction of the colder region () forces the material at to bow towards the colder side to maintain geometric compatibility (zero shear stress).
This causes the points on the y-axis to displace in the negative x-direction, demonstrating that the cavity undergoes non-conformal distortion rather than simple scalar scaling.
Quick Facts About This Question
Question Information
| Subject | Physics |
| Chapter | Thermal Properties of Matter - Class 11 Part 2 |
| Concept | Expansion of Cavities in Solids |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |