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Question #42135

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The Question

A Young's Double Slit Experiment (YDSE) apparatus is constructed entirely from a solid isotropic material with a coefficient of linear thermal expansion α\alpha. The slits are separated by a distance dd and the screen is rigidly attached at a distance DD from the slit plane. The apparatus is illuminated by a coherent light source of wavelength λ\lambda (which remains unaffected by the temperature of the apparatus). Initially, at temperature TT, the nthn^{\text{th}} order bright fringe is observed at a distance yny_n from the central maximum. If the entire apparatus is uniformly heated to a temperature T+ΔTT + \Delta T, what is the shift Δyn\Delta y_n in the position of the nthn^{\text{th}} order bright fringe? (Assume αΔT≪1\alpha \Delta T \ll 1 and retain leading-order terms in αΔT\alpha \Delta T)

Options

  • A.

    −yn3D2αΔT-\frac{y_n^3}{D^2} \alpha \Delta T

  • B.

    0

  • C.

    yn3D2αΔT\frac{y_n^3}{D^2} \alpha \Delta T

  • D.

    ynαΔTy_n \alpha \Delta T

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Variable_Constraint

Develop pure symbolic logic skills by mastering algebraic constraints without relying on numerical data.

Concepts Behind This Question

Expansion of Cavities in Solids|Young's Double Slit Geometry|Binomial Approximation

Why This Question Is Tricky

Common Mistakes

This question tests the limits of the small-angle approximation in wave optics under thermal expansion.

A common trap is for students to mechanically apply the standard fringe position formula yn=nλDdy_n = \frac{n\lambda D}{d}.

If they do this, substituting D′=D(1+αΔT)D' = D(1+\alpha\Delta T) and d′=d(1+αΔT)d' = d(1+\alpha\Delta T) yields yn′=yny_n' = y_n, incorrectly implying a shift of zero (Option B).

However, the small-angle approximation masks the true geometric path difference for higher-order fringes.

The exact condition dsin⁡θ=nλd\sin\theta = n\lambda must be used.

Because the wavelength λ\lambda does not expand with the apparatus, the expansion of the slit separation dd causes the diffraction angle θ\theta to decrease.

A rigorous binomial expansion of tan⁡θ\tan\theta reveals a non-intuitive, non-zero inward shift proportional to yn3/D2y_n^3/D^2.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterThermal Properties of Matter - Class 11 Part 2
ConceptExpansion of Cavities in Solids
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree