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Question #42136

Difficulty: 8/10 | 🟢 Free

The Question

A solid sphere of density ρ1\rho_1 at temperature T0T_0 is released from rest at the surface (y=0y=0) of a deep, non-viscous liquid column. The temperature of the liquid varies with depth yy as T(y)=T0−kyT(y) = T_0 - ky, where kk is a positive constant. The density of the liquid at T0T_0 is ρ2\rho_2, and it is given that ρ1=54ρ2\rho_1 = \frac{5}{4}\rho_2. The volume expansion coefficient of the liquid is γl=5α\gamma_l = 5\alpha and that of the sphere's material is γs=2α\gamma_s = 2\alpha. Assuming αky≪1\alpha k y \ll 1 so that higher-order terms can be neglected, what is the maximum depth HH reached by the sphere before it momentarily comes to rest?

Options

  • A.

    16αk\frac{1}{6\alpha k}

  • B.

    112αk\frac{1}{12\alpha k}

  • C.

    110αk\frac{1}{10\alpha k}

  • D.

    120αk\frac{1}{20\alpha k}

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Explanation

How the Examiner Thinks

Multi-Concept_Bridge

Master problems that require linking physics and math concepts to solve complex competitive questions.

Concepts Behind This Question

Variation of Density with Temperature|Mechanical Energy Conservation|Archimedes Principle

Why This Question Is Tricky

Common Mistakes

This question tests the dynamic coupling of Archimedes' principle with thermal expansion and mechanical energy conservation.

The primary trap is neglecting the thermal contraction of the sphere's volume, which alters the buoyant force alongside the fluid's density gradient.

A secondary, highly lethal trap is confusing the equilibrium position (where net force is zero, yielding 1/(12αk)1/(12\alpha k)) with the maximum depth (where velocity is zero), failing to apply the Work-Energy Theorem to a non-constant force.

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Question Information

SubjectPhysics
ChapterThermal Properties of Matter - Class 11 Part 2
ConceptVariation of Density with Temperature
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree