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Question #42138

Difficulty: 8/10 | 🟢 Free

The Question

A thermally insulated, solid radioactive sphere of initial radius R0R_0, mass mm, and specific heat capacity ss is placed in a vacuum. At t=0t=0, it contains N0N_0 active nuclei with a decay constant λ\lambda. Each decay releases energy QQ, which is completely absorbed by the sphere. The coefficient of linear thermal expansion of the sphere's material is α\alpha. Gamma photons emitted from the center of the sphere travel to the surface, undergoing attenuation according to I=I0e−τI = I_0 e^{-\tau}, where the optical depth τ=μR\tau = \mu R, and the linear attenuation coefficient μ\mu is directly proportional to the instantaneous density ρ\rho of the sphere. If the initial optical depth is τ0\tau_0, which of the following expressions represents the optical depth τ(t)\tau(t) at time tt? (Assume αΔT≪1\alpha \Delta T \ll 1).

Options

  • A.

    τ0[1−2αQN0ms(1−e−λt)]\tau_0 \left[ 1 - \frac{2\alpha Q N_0}{ms} (1 - e^{-\lambda t}) \right]

  • B.

    τ0[1−3αQN0ms(1−e−λt)]\tau_0 \left[ 1 - \frac{3\alpha Q N_0}{ms} (1 - e^{-\lambda t}) \right]

  • C.

    τ0[1+αQN0ms(1−e−λt)]\tau_0 \left[ 1 + \frac{\alpha Q N_0}{ms} (1 - e^{-\lambda t}) \right]

  • D.

    τ0[1−αQN0ms(1−e−λt)]\tau_0 \left[ 1 - \frac{\alpha Q N_0}{ms} (1 - e^{-\lambda t}) \right]

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Explanation

How the Examiner Thinks

Multi-Concept_Bridge

Master problems that require linking physics and math concepts to solve complex competitive questions.

Concepts Behind This Question

Variation of Density with Temperature|Radioactive Decay Law Dynamics|Differential Equations

Why This Question Is Tricky

Common Mistakes

This question tests the coupled dynamics of radioactive decay, thermodynamics, and radiation attenuation.

The primary trap lies in the assumption of either a constant attenuation coefficient μ\mu or failing to account for the simultaneous expansion of the path length R(t)R(t) alongside the density decrease.

Students often incorrectly assume τ(t)∝ρ(t)\tau(t) \propto \rho(t) directly, leading to a fractional change of −3αΔT-3\alpha \Delta T (Option B), or they assume μ\mu is constant and only RR increases, leading to +αΔT+\alpha \Delta T (Option C).

The correct physical model requires recognizing that τ∝ρR∝1/R2\tau \propto \rho R \propto 1/R^2, resulting in a −2αΔT-2\alpha \Delta T dependence, while correctly integrating the exponentially decaying power output to find the temperature state.

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Question Information

SubjectPhysics
ChapterThermal Properties of Matter - Class 11 Part 2
ConceptVariation of Density with Temperature
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree