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Question #42145
The Question
One mole of an ideal monatomic gas is enclosed in a cylinder with a movable piston. Starting at , the gas expands and does work on the piston at a constant rate . Simultaneously, an internal electric heater supplies heat to the gas at a constant rate (where ). The cylinder walls are poorly insulated, resulting in a time-varying heat loss to the surroundings at a rate , where is a positive constant. If the initial temperature of the gas is , what is the maximum temperature reached by the gas during this process? (Here is the universal gas constant)
Options
- A.
- B.
- C.
- D.
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Multi-Concept_Bridge
Master problems that require linking physics and math concepts to solve complex competitive questions.
Concepts Behind This Question
Calorimetry with Heat Loss|Adiabatic/Isothermal Processes via KTG|Integration
Why This Question Is Tricky
Common Mistakes
This question tests the differential application of the First Law of Thermodynamics in non-equilibrium, time-dependent processes.
A common trap for JEE Advanced students is attempting to model the expansion using standard polytropic path equations () or assuming an average heat loss rate.
By introducing a time-varying heat sink () alongside constant power and work rates, the student is forced to abandon equilibrium path assumptions, construct the rate equation , and integrate over time to find the extremum of the internal energy state.
Option D traps students who fail to integrate the linear time dependence correctly, while Option B traps those who carelessly use the diatomic heat capacity.
Quick Facts About This Question
Question Information
| Subject | Physics |
| Chapter | Thermal Properties of Matter - Class 11 Part 2 |
| Concept | Calorimetry with Heat Loss |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |