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Question #42147
The Question
A heating coil is submerged in a calorimeter containing a liquid. The coil is connected to a constant voltage source of . The resistance of the coil at the surrounding temperature is , and its temperature coefficient of resistance is . The calorimeter loses heat to the surroundings according to Newton's law of cooling, with a heat transfer coefficient . Assuming the liquid is continuously stirred and maintains a uniform temperature, what is the steady-state temperature of the liquid?
Options
- A.
- B.
- C.
- D.
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Intuition_Breaker
Train your brain to resist "obvious" answers that are designed to deceive your intuition.
Concepts Behind This Question
Calorimetry with Heat Loss|Internal Resistance Variation|Current Electricity
Why This Question Is Tricky
Common Mistakes
This question tests the student's ability to model a non-linear thermal-electric feedback loop.
A common trap is assuming the power dissipated by the coil remains constant (), which ignores the temperature dependence of the internal resistance.
By doing so, students incorrectly calculate a linear steady-state condition (yielding ), failing to recognize that as the temperature rises, the resistance increases, thereby reducing the Joule heating rate and leading to a lower actual steady-state temperature.
Another trap is incorrectly using while assuming constant current, which yields a physically absurd negative temperature change.
Quick Facts About This Question
Question Information
| Subject | Physics |
| Chapter | Thermal Properties of Matter - Class 11 Part 2 |
| Concept | Calorimetry with Heat Loss |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |