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Question #44965
The Question
Consider the non-standard amino acid 2-amino-3-(4-aminophenyl)propanoic acid (-aminophenylalanine) in an aqueous solution at 298 K. The values for its three ionizable groups are 2.0, 4.6, and 9.2. Calculate the isoelectric point (pI) of this amino acid.
Options
- A.
6.9
- B.
3.3
- C.
5.6
- D.
5.3
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Exception_Exposure
Learn to identify edge cases and boundary exceptions that JEE examiners hide in math problems.
Concepts Behind This Question
Amino Acid Zwitterion pH Sensitivity|Carboxylic Acid Strength|Inductive Effect Trends
Why This Question Is Tricky
Common Mistakes
This question targets a common, fatal heuristic used by students: 'If an amino acid has two values below 7, it acts like an acidic amino acid (e.g., Aspartic acid), and the pI is the average of the two lowest values.' Applying this blindly yields a pI of 3.3 (Option B).
The trap exploits the fundamental difference between a neutral acid ( charge transition, like a side-chain carboxyl group) and a cationic acid ( charge transition, like the anilinium ion here).
Because the of 4.6 belongs to a cationic acid, the molecule transitions from a to a charge state at this pH, making 4.6 the lower bound of the zwitterion, not the upper bound.
Students must draw the actual protonation states rather than relying on numerical pattern matching.
Quick Facts About This Question
Question Information
| Subject | Chemistry |
| Chapter | Biomolecules - Class 12 |
| Concept | Amino Acid Zwitterion pH Sensitivity |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |