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Question #44983

Difficulty: 8/10 | 🟢 Free

The Question

A biochemical mixture contains 1 mole1\text{ mole} each of the following eight compounds in an aqueous solution at 298 K298\text{ K}: (I) β\beta-D-Ribofuranose (II) Adenosine (III) Thymidine 5'-monophosphate (TMP) (IV) 2-Deoxy-β\beta-D-ribofuranose (V) Maltose (VI) Sucrose (VII) Uridine (VIII) Lactose

What is the total number of compounds in this mixture that possess a free hemiacetal/hemiketal group, undergo mutarotation, and yield a silver mirror when treated with Tollens' reagent (\ce[Ag(NH3)2]+/OH−\ce{[Ag(NH3)2]+ / OH-})?

Options

  • A.

    3

  • B.

    4

  • C.

    5

  • D.

    6

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Exception_Exposure

Learn to identify edge cases and boundary exceptions that JEE examiners hide in math problems.

Concepts Behind This Question

Nucleoside vs Nucleotide|Reducing Sugar Criteria|D-Glucose Anomeric Equilibrium

Why This Question Is Tricky

Common Mistakes

The 'Litmus Test' for a reducing sugar is the presence of a free hemiacetal/hemiketal.

Students often fall into the trap of assuming that all nucleotides and nucleosides will reduce Tollens' reagent because they inherently contain a ribose or deoxyribose sugar moiety.

The critical exception tested here is that the formation of the N-glycosidic bond between the C1' anomeric carbon of the sugar and the nitrogenous base effectively locks the anomeric carbon.

This nullifies the ability of the furanose ring to open into the reactive aldehyde form, rendering nucleosides and nucleotides strictly non-reducing.

Quick Facts About This Question

Question Information

SubjectChemistry
ChapterBiomolecules - Class 12
ConceptNucleoside vs Nucleotide
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree