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Question #44989

Difficulty: 8/10 | 🟢 Free

The Question

D-Glyceraldehyde is subjected to the Kiliani-Fischer synthesis. The intermediate cyanohydrins are hydrolyzed and heated to yield a mixture of two stable cyclic compounds, L1\mathbf{L_1} and L2\mathbf{L_2}. Reduction of L1\mathbf{L_1} and L2\mathbf{L_2} with \ceNa(Hg)\ce{Na(Hg)} in water at pH 3-5 yields a mixture of two aldotetroses, X\mathbf{X} and Y\mathbf{Y}. The mixture of X\mathbf{X} and Y\mathbf{Y} is then treated with excess \ceCH3OH\ce{CH_3OH} in the presence of catalytic dry \ceHCl\ce{HCl} to yield a mixture of major products Z\mathbf{Z}.

Let xx be the number of compounds in the mixture L1+L2\mathbf{L_1} + \mathbf{L_2} that exhibit mutarotation in aqueous solution. Let yy be the number of compounds in the mixture X+Y\mathbf{X} + \mathbf{Y} that give a positive Tollens' test. Let zz be the total number of major stereoisomers present in the mixture Z\mathbf{Z}.

Determine the correct set of values for (x,y,z)(x, y, z).

Options

  • A.

    (0,2,4)(0, 2, 4)

  • B.

    (0,2,2)(0, 2, 2)

  • C.

    (2,2,4)(2, 2, 4)

  • D.

    (0,0,4)(0, 0, 4)

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Mechanism_Trap

Don't get tricked by the process! Learn the mechanical traps used in competitive exam questions.

Concepts Behind This Question

Kiliani-Fischer Chain Extension|Reducing Sugar Criteria|D-Glucose Anomeric Equilibrium

Why This Question Is Tricky

Common Mistakes

This problem tests the structural nuances of the Kiliani-Fischer extension and carbohydrate cyclization.

The first trap is confusing lactones (cyclic esters) with hemiacetals, testing the condition for mutarotation.

The second trap tests the criteria for reducing sugars, ensuring students know hemiacetals are in equilibrium with Tollens-active aldehydes.

The final 'Hidden Variable' trap involves Fischer glycosidation of aldotetroses: students who memorize that sugars form 6-membered pyranoses might erroneously assume aldotetroses (having only 4 carbons) cannot cyclize and instead form open-chain dimethyl acetals (yielding z=2).

Recognizing that they form stable 5-membered furanosides yields the correct z=4.

Quick Facts About This Question

Question Information

SubjectChemistry
ChapterBiomolecules - Class 12
ConceptKiliani-Fischer Chain Extension
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree